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Question
a fair coin is tossed 10times .find the probability that two heads do not occur consecutively
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Answer
Download CAT formulas of Permutation and Combinations, which will help you to save time and effort
Answer
10 Tails - 1/(2^10)
9T 1 H - (10C1)/(2^10) = 10/(2^10)
8T 2H - (9C2)/(2^10) = 36/(2^10)
7T 3H - (8C3)/(2^10) = 56/(2^10)
6T 4H - (7C4)/(2^10) = 35/(2^10)
5T 5H - (6C5)/(2^10) = 6/(2^10)
Total = 1+10+36+56+35+ 6/(2^10)
=144/(2^10) = 9/64
