Question 99

∆XYZ is right angled at Y. If m∠X = 60°, then find the value of (secZ + 2/√3)

Solution

Sum of angles of $$\triangle$$ XYZ = $$\angle X+\angle Y+\angle Z=180^\circ$$

=> $$60^\circ+90^\circ+\angle Z=180^\circ$$

=> $$\angle Z=180^\circ-150^\circ=30^\circ$$

To find : $$(\sec Z+\frac{2}{\sqrt3})$$

= $$sec(30^\circ)+\frac{2}{\sqrt3}$$

= $$\frac{2}{\sqrt3}+\frac{2}{\sqrt3}=\frac{4}{\sqrt3}$$

=> Ans - (A)

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