Solution
Sum of angles of $$\triangle$$ XYZ = $$\angle X+\angle Y+\angle Z=180^\circ$$
=> $$60^\circ+90^\circ+\angle Z=180^\circ$$
=> $$\angle Z=180^\circ-150^\circ=30^\circ$$
To find : $$(\sec Z+\frac{2}{\sqrt3})$$
= $$sec(30^\circ)+\frac{2}{\sqrt3}$$
= $$\frac{2}{\sqrt3}+\frac{2}{\sqrt3}=\frac{4}{\sqrt3}$$
=> Ans - (A)
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