If the length of one side and the diagonal of a rectangle are 7 cm and 25 cm respectively, then find its perimeter (in cm).
Let $$l$$ be the length of rectangle and breadth = $$b=7$$ cm
Diagonal of rectangle = $$d=25$$ cm
=> $$(l)^2=(d)^2-(b)^2$$
=> $$(l)^2=(25)^2-(7)^2$$
=> $$(l)^2=625-49=576$$
=> $$l=\sqrt{576}=24$$ cm
$$\therefore$$ Perimeter of rectangle = $$2(l+b)$$
= $$2(24+7)=2\times31=62$$ cm
=> Ans - (C)
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