Δ XYZ is right angled at Y. If m∠Z = 60°, then what is the value of (1/√2) Sec X?
Given : m∠Z = 60° and m∠Y = 90°
=> In $$\triangle$$ XYZ,
=> ∠X + ∠Y + ∠Z = 180°
=> ∠X + 60° + 90° = 180°
=> ∠X = 180° - 150° = 30°
To find : (1/√2) Sec X
= $$sec(30^\circ) \times \frac{1}{\sqrt2}$$
= $$\frac{2}{\sqrt3}\times\frac{1}{\sqrt2}=\frac{2}{\sqrt6}$$
=> Ans - (D)
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