Question 95

Δ XYZ is right angled at Y. If m∠Z = 60°, then what is the value of (1/√2) Sec X?

Solution

Given : m∠Z = 60° and m∠Y = 90°

=> In $$\triangle$$ XYZ,

=> ∠X + ∠Y + ∠Z = 180°

=> ∠X + 60° + 90° = 180°

=> ∠X = 180° - 150° = 30°

To find : (1/√2) Sec X

= $$sec(30^\circ) \times \frac{1}{\sqrt2}$$

= $$\frac{2}{\sqrt3}\times\frac{1}{\sqrt2}=\frac{2}{\sqrt6}$$

=> Ans - (D)

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