Expression : $$(\frac{cosecA}{cotA+tanA})^2$$
= $$[(\frac{1}{sinA})\div(\frac{cosA}{sinA}+\frac{sinA}{cosA})]^2$$
= $$[(\frac{1}{sinA})\div(\frac{sin^2A+cos^2A}{sinAcosA})]^2$$
= $$(\frac{1}{sinA}\times \frac{sinAcosA}{1})^2$$
= $$(cosA)^2=cos^2A$$
= $$1-sin^2A$$
=> Ans - (B)
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