Equation 1Â :Â 4x - 3y = 47
Equation 2Â : 3x + y = 32
Multiplying equation (ii) by 3 and adding it to equation (i)
=> $$(4x+9x)+(-3y+3y)=(47+96)$$
=> $$13x=143$$
=> $$x = \frac{143}{13}=11$$
Substituting it in equation (ii), => $$y=32-3(11) = 32 - 33 = -1$$
$$\therefore (x,y)=(11,-1)$$
=> Ans - (C)
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