Question 95

If $$\dfrac{1}{\sqrt{(1+tan^2A)}}$$ = x, then the value of x is

Solution

Expression : $$\frac{1}{\sqrt{1 + tan^2 A}}$$

Using $$(sec^2 A - tan^2 A = 1)$$

= $$\frac{1}{\sqrt{sec^2 A}} = \frac{1}{sec A}$$

= $$cos A$$

=> Ans - (D)

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