$$\frac{34 \times 4-12 \times 8}{6^{2}+\sqrt{196}+(11)^{2}}=?$$

Solution

We need to find the value of $$\frac{34 \times 4-12 \times 8}{6^{2}+\sqrt{196}+(11)^{2}}$$

Let us first calculate the numerator, $$34 \times 4 - 12 \times 8 = 136 - 96 = 40$$
The denominator equals $$6^2 + \sqrt{196} +11^2 = 36 +14 +121 = 171$$

Hence, the fraction equals $$\frac{40}{171}$$

Share on Whatsapp Share on Whatsapp

Create a FREE account and get:

Banking Quant Shortcuts PDF
Free Banking Study Material - (15000 Questions)
135+ Banking previous papers with solutions PDF
100+ Online Tests for Free

SBI Clerk ES 22-11-2009

$$\frac{34 \times 4-12 \times 8}{6^{2}+\sqrt{196}+(11)^{2}}=?$$

Login to your Cracku account

Hello! 👋

Ready to Unlock Your Success?

Please Enter Your OTP

Please enter the following details

Create a free Cracku account