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What should come in place of question mark (?) in the following questions?
Solution
We need to find the value of $$\frac{34 \times 4-12 \times 8}{6^{2}+\sqrt{196}+(11)^{2}}$$
Let us first calculate the numerator, $$34 \times 4 - 12 \times 8 = 136 - 96 = 40$$
The denominator equals $$6^2 + \sqrt{196} +11^2 = 36 +14 +121 = 171$$
Hence, the fraction equals $$\frac{40}{171}$$
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