Question 90

$$\sqrt{\frac{(1 + tan^{2}A)}{tan^2A}}$$ is equal to

Solution

Expression : $$\sqrt{\frac{(1 + tan^{2}A)}{tan^2A}}$$

$$\because (sec^2A-tan^2A=1)$$

= $$\sqrt{\frac{sec^2A}{tan^2A}} = \frac{secA}{tanA}$$

= $$\frac{1}{cosA} \div \frac{sinA}{cosA}$$

= $$\frac{1}{cosA} \times \frac{cosA}{sinA}$$

= $$\frac{1}{sinA} = cosecA$$

=> Ans - (C)

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