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Question 90
In the given figure, PQRS is a trapezium in which PMIISN, NR = 9 cm, PS = 12 cm, QM= NR and NR = SN. What is the area $$(in cm^{2})$$ of trapezium?Â
Solution
QR = 9+12+9 = 30 cm
Area of trapezium = $$\frac{1}{2}\times h\times$$ (sum of parallel sides)
= $$\frac{1}{2}\times9\times(12+30)$$
= $$21\times9=189$$ $$cm^2$$
=> Ans - (C)
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