Question 90

In the given figure, PQRS is a trapezium in which PMIISN, NR = 9 cm, PS = 12 cm, QM= NR and NR = SN. What is the area $$(in cm^{2})$$ of trapezium?

Solution

QR = 9+12+9 = 30 cm

Area of trapezium = $$\frac{1}{2}\times h\times$$ (sum of parallel sides)

= $$\frac{1}{2}\times9\times(12+30)$$

= $$21\times9=189$$ $$cm^2$$

=> Ans - (C)

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