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If $$\cos \theta = \frac{x^2 - y^2}{x^2 + y^2}$$ then the value of $$\cot \theta$$ is equal to [If $$0 \leq \theta \leq 90^\circ$$]
$$\frac{2xy}{x^2 - y^2}$$
$$\frac{2xy}{x^2 + y^2}$$
$$\frac{x^2 + y^2}{2xy}$$
$$\frac{x^2 - y^2}{2xy}$$
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