Question 90

40 liters of milk contains 10% of water. How many liters of water are to be added to increase the water content to 20%?

Solution

Given: Amount of mixture = 40L

Water content in the mixture = 10% of 40 = 40 x $$\frac{10}{100}$$ = 4L

So, milk content in the mixture will be = 40 - 4 = 36L

Let the amount of water need to be added to make the water content to 20% be xL.

Then, $$\frac{4+x}{40+x}$$ x 100 = 20

x = 5L

Hence, option C is correct.

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