The ratio of milk and water in three samples is 1: 3, 3: 5 and 11: 5. A mixture containing equal quantities of all three samples is made. What will be the ratio of milk and water in the new mixture?

Let quantity of each sample is L.C.M. (4,8,16) = 16 unit

=> Milk in first sample = $$\frac{1}{(1+3)}\times16=4$$ unit

and water in first sample = $$16-4=12$$ units

Similarly, milk in second sample = $$\frac{3}{(3+5)}\times16=6$$ units and water = $$16-6=10$$ units

Milk in third sample = $$\frac{11}{(11+5)}\times16=11$$ units and water = $$16-11=5$$ units

$$\therefore$$ Ratio of milk and water in the new mixture = $$\frac{(4+6+11)}{(12+10+5)}$$

= $$\frac{21}{27}=\frac{7}{9}$$

=> Ans - (A)