In an alloy, lead and tin are in the ratio of 2 : 3. In the second alloy, the ratio of same elements is 3 : 4. If equal quantities of these two alloy are mixed to form a new alloy, then what will be the ratio of these two elements in the new alloy?

Ratio of lead and tin in first alloy = 2 : 3

Ratio of lead and tin in second alloy = 3 : 4 

Let quantity of both alloys taken = L.C.M. (5,7) = 35 units

=> Lead in first alloy = $$\frac{2}{(2+3)}\times35=14$$ units

Tin present in first alloy = $$35-14=21$$ units

Similarly, lead in second alloy = $$15$$ units and tin = $$20$$ units

$$\therefore$$ Ratio of lead and tin in the new alloy = $$\frac{(14+15)}{(21+20)}$$

= $$\frac{29}{41}$$

=> Ans - (B)