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Question 9


Five charges $$+q, +5q, -2q, +3q$$ and $$-4q$$ are situated as shown in the figure.

image

The electric flux due to this configuration through the surface $$S$$ is :

Inside surface SSS enclosed charges are:

$$+5q,\quad+q,\quad-2q$$

Charges +3q and −4q are outside, so contribute zero net flux through closed surface.

Net enclosed charge:

$$Q_{enc}=5q+q-2q=4q$$

By Gauss law,

$$\Phi=\frac{Q_{enc}}{\epsilon_0}$$

So,

$$\frac{4q}{\epsilon_0}$$

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