Five charges $$+q, +5q, -2q, +3q$$ and $$-4q$$ are situated as shown in the figure.

The electric flux due to this configuration through the surface $$S$$ is :

Inside surface SSS enclosed charges are:

$$+5q,\quad+q,\quad-2q$$

Charges +3q and −4q are outside, so contribute zero net flux through closed surface.

Net enclosed charge:

$$Q_{enc}=5q+q-2q=4q$$

By Gauss law,

$$\Phi=\frac{Q_{enc}}{\epsilon_0}$$

So,

$$\frac{4q}{\epsilon_0}$$

Create a FREE account and get:

Predict your JEE Main percentile, rank & performance in seconds

Check Your Score Now

Ask our AI anything

AI can make mistakes. Please verify important information.

Download resources