Question 9

A cylinder with base radius 8 cm and height 2 cm is melted to form a cone of height 6 cm, The radius of the cone will be

Solution

solution

base radius r = 8

height of cylinder = 2

height of cone = 6

volume of the cylinder and cone remains the same

volume of cylinder = volume of cone

$$\pi r^2 h$$ = $$\frac{1}{3} \pi r^2 h$$ {substituting the values}

$$\pi 8^2 \times 2$$ = $$\frac{1}{3}\pi r^2 \times 6$$

$$8^2 \times 2$$ = $$\frac{1}{3} r^2 \times 6$$

$$8^2$$ = $$ r^2 $$

radius of cone = 8cm

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