A cylinder with base radius 8 cm and height 2 cm is melted to form a cone of height 6 cm, The radius of the cone will be
solution
 base radius r = 8
 height of cylinder = 2
height of cone = 6
volume of the cylinder and cone remains the same
volume of cylinder = volume of cone
$$\pi r^2 h$$ =Â $$\frac{1}{3} \pi r^2 h$$ {substituting the values}
$$\pi 8^2 \times 2$$Â =Â $$\frac{1}{3}\pi r^2 \times 6$$Â
$$8^2 \times 2$$Â =Â $$\frac{1}{3} r^2 \times 6$$Â
$$8^2$$ =Â $$Â r^2 $$Â
radius of cone = 8cm
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