Question 89

What is the sum of the first 13 terms of an arithmetic progression if the first term is -10 and last term is 26?

Solution

$$S_{n}=\frac{n}{2}[a+l]$$

$$S_{13}=\frac{13}{2}[-10+26]$$

$$S_{13}=\frac{13}{2}[16]=104$$

So the answer is option A.

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