The given pie-chart shows the break-up of total marks obtained by a student in five subjects A, B, C, D and E. The maximum marks in each subject is 150 and he obtained total of 600 marks.

The total marks obtained by the student in subjects C and E is approximately how much per cent more than what he obtained in A and D together?

The total marks obtained by the student in subjects C and E = 68 + 76 = 144$$\degree$$
The total marks obtained by the student in subjects C and E = 600 $$\times \frac{144}{360} = 240$$
The total marks obtained by the student in subjects A and D = 60 + 72 = 132$$\degree$$
The total marks obtained by the student in subjects A and D = 600 $$\times \frac{132}{360} = 220$$

Required percentage = $$\frac{240 - 220}{220} \times 100 = \frac{20}{220} \times 100$$ = 9.09%