Solution
We raise all the terms to an equal power. Let's take the 12th power of each term.
We get $$6^4,\ 10^3\ and\ 3^6$$
The value of the 4th power of 6 is easily over 1000, which is nothing but cube of 10. And lastly 6th power of 3 is 729.
Hence, the descending order of the terms would be the answer option.
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