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Question 89
The 7th and 12th term of an arithmetic progression are -15 and 5 respectively. What is the 16th term?
Solution
$$T_{7}$$ = a + 6d = -15-------(1)
$$T_{12}$$ = a + 11d = 5-------(2)
on solving (1) AND (2)
d = 4 & a = -39
$$T_{16}$$ = a + 15d = -39 + 15(4) = 21
so the answer is option C.
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