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Question 89
The 3rd and 6th term of an arithmetic progression are 13 and -5 respectively. What is the 11th term?
Solution
$$T_{3}$$ = a + 2d = 13-------(1)
$$T_{6}$$ = a + 5d = -5-------(2)
on solving (1) AND (2)
d = -6 & a = 25
$$T_{11}$$ = a + 10d = 25 + 10(-6) = -35
so the answer is option D.
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