Question 89

The 3rd and 6th term of an arithmetic progression are 13 and -5 respectively. What is the 11th term?

Solution

$$T_{3}$$ = a + 2d = 13-------(1)

$$T_{6}$$ = a + 5d = -5-------(2)

on solving (1) AND (2)

d = -6 & a = 25

$$T_{11}$$ = a + 10d = 25 + 10(-6) = -35

so the answer is option D.

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