Question 89

In Δ ABC, the median AD is 7 cm and CB is 14 cm, measure of ∠CAB is

Solution

AD = 7 cm and BC = 14 cm

Since, AD is the median, => BD = DC = 7 cm

In $$\triangle$$ ADC, => AD = CD = 7 cm

=> $$\angle$$ DCA = $$\angle$$ DAC = 45°

Similarly, in $$\triangle$$ ADB => $$\angle$$ DAB = 45°

$$\therefore$$ $$\angle$$ CAB = $$\angle$$ DAC + $$\angle$$ DAB = 45° + 45° = 90°

=> Ans - (C)

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