Question 89

If sinA/(1 + cosA) = x, then x is

Solution

Expression : $$\frac{sinA}{1+cosA}$$

Multiplying both numerator and denominator by $$(1-cosA)$$

= $$\frac{sinA}{1+cosA}$$ $$\times \frac{(1-cosA)}{(1-cosA)}$$

= $$\frac{sinA(1-cosA)}{1-cos^2A} = \frac{sinA(1-cosA)}{sin^2A}$$

= $$\frac{1-cosA}{sinA} = (\frac{1}{sinA}-\frac{cosA}{sinA})$$

= $$cosecA-cotA$$

=> Ans - (D)

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