Question 89

An engineering student has to secure 25% marks to pass. He gets 56 and fails by 34 marks. Find the maximum marks.

Solution

Let maximum marks = $$100x$$

=> Passing marks = $$\frac{25}{100} \times 100x = 25x$$

According to ques,

=> $$25x - 34 = 56$$

=> $$25x = 56 + 34 = 90$$

=> $$x = \frac{90}{25} = 3.6$$

$$\therefore$$ Maximum marks = $$100 \times 3.6 = 360$$

Create a FREE account and get:

Free SSC Study Material - 18000 Questions
230+ SSC previous papers with solutions PDF
100+ SSC Online Tests for Free

CAT Quant Questions | CAT Quantitative Ability

CAT Number Systems Questions CAT Remainders Questions CAT Progressions and Series Questions CAT Profit And Loss Questions CAT Arithmetic Questions

CAT DILR Questions | LRDI Questions For CAT

CAT Data change over a period Questions CAT Charts Questions CAT Games and Tournamnents Questions CAT DI with connected data sets Questions CAT Truth Lie Concept Questions

CAT Verbal Ability Questions | VARC Questions For CAT

CAT Reading Comprehension Questions CAT Verbal Ability Questions CAT Miscellaneous Questions CAT Para Jumbles Questions CAT Para Summary Questions

Follow us on

Boost your Prep!

Download App