A fraction is greater than its reciprocal by 9/20. What is the fraction?
Let that fraction be $$\frac{1}{x}$$
$$ (\frac{1}{x}) = x + 9/20$$
$$\Rightarrow 20x^{2}+9x-20 = 0$$
$$\Rightarrow(x+\frac{25}{20})(x-\frac{16}{20})=0$$
$$\Rightarrow(x+5/4)(x-4/5)=0$$
$$\Rightarrow x = -5/4 or 4/5$$
$$\Rightarrow \text{fraction} = \frac{1}{x} = -4/5 \text(or) 5/4$$
so the answer is option A.
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