Question 87

If sin3A = x, then value of x is

Solution

Expression : sin3A = X

= $$sin(2A+A)$$

= $$sin(2A)cosA+cos(2A)sinA$$

= $$(2sinAcosA)cosA + (1-2sin^2A)sinA$$

= $$2sinA(cos^2A) + sinA - 2sin^3A$$

= $$2sina(1-sin^2A)+sinA-2sin^3A$$

= $$2sinA-2sin^3A+sinA-2sin^3A$$

= $$3sinA-4sin^3A$$

=> Ans - (D)


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