A thief is stopped by a policeman from a distance of 250 metres. When the policeman starts the chase, the thief also starts running. Assuming the speed of the thief as 5 km/h and that of police man as 7 km/h, how far the thief would have run, before he is over­-taken?

Since the thief is escaping from the police man, thus they both are running in same direction.

Speed of thief = 5 km/hr and speed of policeman = 7 km/hr

=> Relative speed = 7 - 5 = 2 km/hr

Distance between them = 250 metres = 0.25 km

=> Time taken = $$\frac{distance}{speed}$$

= $$\frac{0.25}{2} = \frac{1}{8}$$ hr

$$\therefore$$ Distance covered by thief before he was caught = $$5 \times \frac{1}{8}$$

= 0.625 km = 625 metres

=> Ans - (D)