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If x + (1/x) = 2, then what is the value of $$x^{64}+x^{121}$$ ?
0
1
2
- 2
x + (1/x) = 2
we can substitute x = 1
$$x^{64}+x^{121}$$=$$1^{64}+1^{121}$$=$$1+1$$=$$2$$
so the answer is option C.
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