Two trains are moving in the opposite direction at speed of 30 km/hr and 45 km/hr respectively, whose lengths are 450 m and 550 m respectively. What is the time taken (in seconds) by slower train to cross the faster train?
Since, the trains are moving in opposite directions, relative speed of train = 30 + 45 = 75 km/hr
= $$(75\times\frac{5}{18})$$ m/s = $$\frac{125}{6}$$ m/s
Sum of lengths of trains = 450 + 550 = 1000 m
Time taken = length/speed
= $$\frac{1000}{\frac{125}{6}}$$
=Â $$1000\times\frac{6}{125}=48$$ sec
=> Ans - (A)
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