Question 84

If $$\frac{sinA}{\sqrt{(1 - sin^{2}A)}}=x$$, then the value of x is

Solution

Expression : $$\frac{sinA}{\sqrt{(1 - sin^{2}A)}}=x$$

$$\because (sin^2A+cos^2A=1)$$

= $$\frac{sinA}{\sqrt{cos^2A}} = \frac{sinA}{cosA}$$

= $$tanA$$

=> Ans - (A)

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