Question 84

Find k, if the line 2x - 3y = 11 is perpendicular to the line 3x + ky = 4?

Solution

Slope of line 2x - 3y = 11 is $$\frac{-2}{-3}$$

= $$\frac{2}{3}$$

Slope of line 3x + ky = 4 is $$\frac{-3}{k}$$

Also, product of slopes of two perpendicular lines is -1

=> $$\frac{2}{3} \times \frac{-3}{k} = -1$$

=> $$\frac{-2}{k} = -1$$

=> $$k = -2 \times -1 = 2$$

=> Ans - (D)

Share on Whatsapp Share on Whatsapp

Create a FREE account and get:

Find k, if the line 2x - ­3y = 11 is perpendicular to the line 3x + ky = ­4?