Question 83

Walking at 60% of his usual speed, a man reaches his destination 1 hour 40 minuteslate, His usual time (in hours) to reach the destination is:

Solution

Let the usual speed be 100 km/hr
Speed = 60 km/hr
Ratio of speed = 5 : 3
Ratio of tiime = 3 : 5
Difference in time ratio = 2 unit
2 unit = 1 hour 40 minutes = 5/3 hhr
3 units = $$\frac{5}{6} \times 3 = \frac{5}{2} = 2 \frac{1}{2}$$
Usual time to reach the destination is $$2 \frac{1}{2}$$ hours.

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SSC CGL Tier-2 13th September 2019 Maths

Walking at 60% of his usual speed, a man reaches his destination 1 hour 40 minuteslate, His usual time (in hours) to reach the destination is:

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