JEE WhatsApp Group
Sign in
Please select an account to continue using cracku.in
↓ →
JEE WhatsApp Group
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
The area of the region given by $$\{(x, y) : xy \leq 8, 1 \leq y \leq x^2\}$$ is :
$$\text{Area} = \int_{1}^{2} (x^2 - 1)dx + \int_{2}^{8} \left(\frac{8}{x} - 1\right)dx$$
$$= \left( \frac{x^3}{3} \right)_{1}^{2} + 8(\ln x)_{2}^{8} - (x)_{1}^{8}$$
$$= \frac{7}{3} + 8(2\ln 2) - 7$$
$$= 16\ln 2 - \frac{14}{3}$$
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.