🎊 Cracku turns 10 🥳 Get upto 75% Off on CAT 2024 courses (8-10th July). Enroll now
Edit MetaData
A small hole of area of cross-section $$2 mm^2$$ is present near the bottom of fully filled open tank of height 2m. Taking $$g = 10 m/s^2$$, the rate of flow of water through the open hole would be nearly :
$$8.9 \times 10^{-6} m^3/s$$
$$2.23 \times 10^{-6} m^3/s$$
$$6.4 \times 10^{-6} m^3/s$$
$$12.6 \times 10^{-6} m^3/s$$
Create a FREE account and get:
Login to your Cracku account.
Follow us on
Incase of any issue contact support@cracku.in
Boost your Prep!
Quick, easy and effective revision