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A small hole of area of cross-section $$2 mm^2$$ is present near the bottom of fully filled open tank of height 2m. Taking $$g = 10 m/s^2$$, the rate of flow of water through the open hole would be nearly :
$$8.9 \times 10^{-6} m^3/s$$
$$2.23 \times 10^{-6} m^3/s$$
$$6.4 \times 10^{-6} m^3/s$$
$$12.6 \times 10^{-6} m^3/s$$
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