Question 82

The number of Positive integers x such that 2018, 1998 and x are the sides of a triangle is

Solution

As 2018,1998 and x are the side of triangle.

Then sum of two sides should be greater than the third side.

So,$$2018+1998>x$$

or,$$4016>x.$$

revesely,$$1998+x>2018.$$

So, minimum value of X should be 21 .

And maximum value of X should be 4016.

So,x can take$$(4016-21)=3995$$ values.

D is correct choice.

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