Question 81

Two identical circles intersect such that their centers and their points of intersection, form a square of side 4cm. Then the area (in sq.cms) of the portion that is common to the two circles is

Solution

Share

Side of the square is 4 cm.

So,radii of the two circles are also 4 cms.

So, area of the one of the arc is 

$$(π×4^2/4)=4π.$$

Area of the square is$$=4×4=16cm^2.$$

clearly the common sector have the half of square common to it.

So,area of one arc is

$$4π-16/2=4π-8 cm^2$$

So,Total area of the arc is$$8π-16$$

$$=8(π-2).$$

A is correct choice.

Get AI Help

Create a FREE account and get:

  • Download Maths Shortcuts PDF
  • Get 300+ previous papers with solutions PDF
  • 500+ Online Tests for Free

Book Free CAT Mentorship

Get personalized CAT strategy from a 99%iler

500+ students mentored
CAT mentor

Join CAT 2026 course by 5-Time CAT 100%iler

Start your IIM journey with the right preparation and crack CAT 2026.

Enroll Now
Ask AI