Question 82

The decreasing order of bond angles in $$\text{BF}_3$$, $$\text{NH}_3$$, $$\text{H}_2\text{O}$$, $$\text{I}_3^-$$

Solution

$$\text{I}_3^-$$ is linear ($$180^\circ$$), $$\text{BF}_3$$ is trigonal planar ($$120^\circ$$), $$\text{NH}_3$$ is pyramidal (about $$107^\circ$$) and $$\text{H}_2\text{O}$$ is bent (about $$104.5^\circ$$). So the decreasing order is $$\text{I}_3^- > \text{BF}_3 > \text{NH}_3 > \text{H}_2\text{O}$$.

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