Question 82

Let $$x = (633)^{24} - (277)^{38} + (266)^{54}$$. What is the units digit of x ?

Solution

$$x = (633)^{24} - (277)^{38} + (266)^{54}$$For the unit digit,
24 = 4 $$\times 6 + 0(remainder)
38 = 4 $$\times 9 + 2(remainder)
54 = 4 $$\times 13 + 2(remainder)
Now,
(Base number unit digit)$$^{remainder}$$
= $$(3)^0 - (7)^2 + (6)^2$$
On consider unit digit,
= 1 - 9 + 6 = 7 - 9
or 17 - 9 = 8
8 is the units digit of x.

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SSC CGL Tier-2 11th September 2019 Maths

Let $$x = (633)^{24} - (277)^{38} + (266)^{54}$$. What is the units digit of x ?

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