Question 82

If 1/√(1 - $$sin^2A$$) = x, then the value of x is

Solution

Expression : $$\frac{1}{\sqrt{1 - sin^2 A}}$$

We know that, $$(1 - sin^2 A) = cos^2 A$$

Taking square root on both sides, => $$\sqrt{1 - sin^2 A} = \sqrt{cos^2 A} = cos A$$

Substituting it in above equation, we get

= $$\frac{1}{cos A} = sec A$$

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If 1/√(1 ­- $$sin^2A$$) = x, then the value of x is