Question 81

The length of the diameter of the circle is 10 cm and length of the chord drawn in a circle is 6 cm. Find the distance (in cm) of chord from the center.

Solution

Given : Diameter = 10 cm and AB = 6 cm

To find : OM = ?

Solution : Radius OB = $$\frac{10}{2}=5$$ cm

Also, MB = $$\frac{6}{2}=3$$ cm

In right $$\triangle$$ OMB

=> $$(OM)^2=(OB)^2-(MB)^2$$

=> $$(OM)^2=(5)^2-(3)^2$$

=> $$(OM)^2=25-9=16$$

=> $$OM=\sqrt{16}=4$$ cm

=> Ans - (D)

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