Question 81

If x + 3 ≤ 4x + 4 and 5(4 - x) - 4 ≥ 5x -2; then the value of x can be

Solution

Expression 1 : x + 3 ≤ 4x + 4

=> $$4x - x \geq 3 - 4$$ => $$3x \geq -1$$

=> $$x \geq \frac{-1}{3}$$ -------------(i)

Expression 2 : 5(4 - x) - 4 ≥ 5x -2

=> $$20 - 5x - 4 \geq 5x - 2$$

=> $$10x \leq 18$$ => $$5x \leq 9$$

=> $$x \leq \frac{9}{5}$$ ------------(ii)

Combining inequalities (i) and (ii), we get : $$\frac{-1}{3} \leq x \leq \frac{9}{5}$$

The possible value of $$x = 0 , 1$$

=> Ans - (C)


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