Question 81

If the height of the equilateral triangle is 2√3 cm, then determine the area (in $$cm^{2}$$) of the equilateral triangle.

Solution

Let side of the equilateral triangle = $$s$$ cm

Median = Height of triangle = $$2\sqrt3=\frac{\sqrt3s}{2}$$

=> $$s=2\times2=4$$ cm

$$\therefore$$ Area of the equilateral triangle = $$\frac{\sqrt3}{4} (s)^2$$

= $$\frac{\sqrt3}{4}\times(4)^2$$

= $$4\sqrt3$$ $$cm^2$$

=> Ans - (C)

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