If the height of the equilateral triangle is 2√3 cm, then determine the area (in $$cm^{2}$$) of the equilateral triangle.
Let side of the equilateral triangle = $$s$$ cm
Median = Height of triangle = $$2\sqrt3=\frac{\sqrt3s}{2}$$
=> $$s=2\times2=4$$ cm
$$\therefore$$ Area of the equilateral triangle = $$\frac{\sqrt3}{4} (s)^2$$
= $$\frac{\sqrt3}{4}\times(4)^2$$
= $$4\sqrt3$$ $$cm^2$$
=> Ans - (C)
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