Question 80
An engineering student has to secure 25% marks to pass. He gets 47 and fails by 43 marks. What are the maximum marks of the examination?
Solution
Let maximum marks = $$100x$$
=> Passing marks = $$\frac{25}{100} \times 100x = 25x$$
According to ques,
=> $$25x - 43 = 47$$
=> $$25x = 47 + 43 = 90$$
=> $$x = \frac{90}{25} = \frac{18}{5}$$
$$\therefore$$ Maximum marks = $$100 \times \frac{18}{5} = 360$$
=> Ans - (C)
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