If the coefficients of the middle terms in the binomial expansions of $$(1 + \alpha x)^{26}$$ and $$(1 - \alpha x)^{28}$$, $$\alpha \neq 0$$, are equal, then the value of $$\alpha$$ is:

A

1

B

$$\frac{14}{13}$$

C

$$\frac{27}{7}$$

D

$$\frac{7}{27}$$