Question 79
Determine the value of $$'x'$$ if $$x=\frac{(943+864)^{2}-(943-864)^{2}}{(1886\times1728)}$$
Solution
Expression : $$x=\frac{(943+864)^{2}-(943-864)^{2}}{(1886\times1728)}$$
Using, $$a^2-b^2=(a+b)(a-b)$$, where $$a=(943+864)$$ and $$b=(943-864)$$
= $$\frac{[(943+864)+(943-864)]\times[(943+864)-(943-864)]}{(1886\times1728)}$$
= $$\frac{(943+943)\times(864+864)}{(1886\times1728)}$$
= $$\frac{(1886)\times(1728)}{(1886\times1728)}=1$$
=> Ans - (A)
Get AI Help?
Create a FREE account and get:
- Free SSC Study Material - 18000 Questions
- 230+ SSC previous papers with solutions PDF
- 100+ SSC Online Tests for Free
