Question 77

Point Q(-2,b) is the midpoint of segment EF. Co-ordinates of E are (-7,-6) and F are (a,0). What is the value of a and b?

Solution

Coordinates of mid point of line joining points $$(x_1,y_1)$$ and $$(x_2,y_2)$$ = $$(\frac{x_1+y_1}{2},\frac{x_2+y_2}{2})$$

Coordinates of E(-7,-6) and F(a,0). Mid point of EF is Q(-2,b)

=> $$-2 = \frac{-7+a}{2}$$

=> $$a-7=-4$$

=> $$a=7-4=3$$

Similarly, $$b = \frac{-6+0}{2}$$

=> $$b=\frac{-6}{2}=-3$$

=> Ans - (A)

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