In university M, $${8 \over {21}}$$ of the Assistant Professors are males and in university L, $${3 \over 5}$$ of the Assistant Professors are males. What is the respective ratio between male assistant Professors in university M and that in university L?
Solution
Number of Assistant Professors in university M = $$\frac{63}{100} \times 100 = 63$$
=> Male assistant professors = $$\frac{8}{21} \times 63 = 24$$
Number of Assistant Professors in university L = $$\frac{80}{100} \times 150 = 120$$
=> Male assistant professors = $$\frac{3}{5} \times 120 = 72$$
$$\therefore$$ Required ratio = $$\frac{24}{72} = 1 : 3$$
