Instructions
Based on the following table answer the given questions.
Solution
Number of Assistant Professors in university K = $$\frac{75}{100} \times 180 = 135$$
Number of Assistant Professors in university L = $$\frac{80}{100} \times 150 = 120$$
Number of Assistant Professors in university M = $$\frac{63}{100} \times 100 = 63$$
=> Total number of Assistant Professors in universities K, L and M = 135 + 120 + 63 = 318
$$\therefore$$ Required average = $$\frac{318}{3} = 106$$
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