Question 77

If 3A = 7B = 13C, then A : B : C is equal to

Solution

Let $$3A = 7B = 13C = k$$

=> $$A = \frac{k}{3}$$ , $$B = \frac{k}{7}$$ , $$C = \frac{k}{13}$$

=> Ratio of A : B : C = $$\frac{k}{3} : \frac{k}{7} : \frac{k}{13}$$

= $$\frac{1}{3}$$ : $$\frac{1}{7}$$ : $$\frac{1}{13}$$

L.C.M. of 3,7 and 13 = 273, thus multiplying by 273, we get :

= $$\frac{273}{3} : \frac{273}{7} : \frac{273}{13}$$

= 91 : 39 : 21

=> Ans - (D)

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