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Question 76
A container contains 40 liters of milk. From this container 4 liters of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?
Solution
If a container contains $$x$$ units of a liquid from which $$y$$ units are taken out and replaced by water. After $$n$$ operations, quantity of pure liquid
= $$x(1-\frac{y}{x})^n$$
$$\therefore$$ Milk in the container now = $$40(1-\frac{4}{40})^3$$
= $$40(\frac{9}{10})^3$$
= $$40\times\frac{729}{1000}$$
= $$\frac{729}{25}=29.16$$ liters
=> Ans - (D)
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